# kolkaoksit is defined as the run legnths encoding of the kokkalsoi sequnece
# we need to omcpute one hundred terms of hte kolksaoksi systme
# secuqnece
# so we need one hundred runs lenghts of the kolakoasi sequcense to liost at
# ksf

koklklk = [1, 2, 2, 1, 1, 2, 1, 2, 2, 1, 2, 2, 1, 1, 2, 1, 1, 2, 2, 1, 2, 1, 1, 2, 1, 2, 2, 1, 1, 2, 1, 1, 2, 1, 2, 2, 1, 2, 2, 1, 1, 2, 1, 2, 2, 1, 2, 1, 1, 2, 1, 1, 2, 2, 1, 2, 2, 1, 1, 2, 1, 2, 2, 1, 2, 2, 1, 1, 2, 1, 1, 2, 1, 2, 2, 1, 2, 1, 1, 2, 2, 1, 2, 2, 1, 1, 2, 1, 2, 2, 1, 2, 2, 1, 1, 2, 1, 1, 2, 2, 1, 2, 1, 1, 2, 1, 2, 2, 1, 2, 2, 1, 1, 2, 1, 1, 2, 1, 2, 2, 1, 1, 2, 1, 1, 2, 2, 1, 2, 1, 1, 2, 1, 1, 2, 2, 1, 2, 2, 1, 1, 2, 1, 2, 2, 1, 2, 1, 1, 2, 2, 1]
koklslk = []

# too kkkkkeep track of whk where' lookings
lookins  = 1 # tmeporaory
lookings = 0 # i forgotr why  ityped this
#ok
#OH IForgot
# ocunt
count = 0


for i in koklklk:
    tmeproary = i
    if tmeproary == lookins:
        count +=1
    else:
        koklslk.append(count)
        count = 1
    lookins = tmeproary
print(koklslk)